The voltage Divider is widespread in electronics because they allow an optimal way to solve the problem of voltage regulation. There are different schematic solutions: from the simplest, for example, in some wall lamps to complex, as the boards shift control windings of the normalizers of the mains voltage.
What is the voltage divider? The wording is simple – it is a device that, depending on the transmission coefficient (configured separately) adjusts the value of the output voltage relative to the input.
Previously, the stores could often be found on the lamp, wall lamp, designed for two lamps. It was the fact that the lamp was designed to work with a voltage of 127 Volts. Thus, the whole system is connected to a household outlet with 220 and worked quite successfully. No miracles! The fact is that the method of connection of conductors formed nothing like a voltage divider. Remember the basics of electrical engineering, namely parallel and serial connection of consumers. As you know, when consistent method of incorporating the strength of the current is equal, and the voltage change (remember Ohm's law). So in the example with the same type of lamp bulb connected in series, reducing their supply voltage twice (110 In). Also a voltage divider can be found in the device that distributes the signal from one antenna to several TVs. In fact, many examples.
Let's look at a simple voltage divider based on two resistors R1 and R2. Resistance connected in series, on the free terminals receiving input voltage U. From the midpoint of the conductor connecting resistors, there is an additional output. So three ends: two – external leads (between them the full value of the voltage U) and the average forming U1 and U2.
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Perform the calculation of the voltage divider, using Ohm's law. Since I = U / R, U is the product of current times resistance. Accordingly, in the area R1, the voltage is U1, and R2 will be U2. The line current is (series connection). Given the law for the complete chain, we find that the supply of U is the sum of U1+U2.
What is the current under these conditions? Summarizing the equations, we get:
I = U / (R1+R2).
Here you can define the value of the voltage (U exit) at the output of the divider (it can be as U1 and U2):
Exit U = U * R2 / (R1+R2).
The dividers in the adjustable resistors there are a number of important features that need to be considered both at the stage of calculations, and in operation.
First of all, such solutions cannot be used to adjust the voltage of powerful consumers. For example, in this way it is impossible to supply power to the motor. One of the reasons – is the values themselves of the resistors. Resistance in kW and if there are, then imagine a massive device that dissipates a large portion of energy as heat.
The Value of the resistance of the connected load should not be less than the electrical resistance of the divider, otherwise the whole system will need to be recalculated. Ideally, the difference R of the divisor and R the load should be as large. It is important to adjust the values of R1 and R2, since the inflated values will result in an excessive voltage drop, and low will overheat, wasting energy on heating.
Calculating the divider, usually pick up the value of his current is several times (e.g., 10) is greater than the amperage of the connected load. Further, knowing the current and voltage, calculate the total resistance (R1+R2). Further, in tables, select the nearest standard value R1 and R2 (given their capacity to avoid over-heating).
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Alin Trodden - author of the article, editor
"Hi, I'm Alin Trodden. I write texts, read books, and look for impressions. And I'm not bad at telling you about it. I am always happy to participate in interesting projects."
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